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Word
problems on percentage will help us to solve various types of problems related
to percentage. Follow the procedure to solve similar type of percent problems.
Word Problems on Percentage Video
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Word problems on percentage:
1. In an exam Ashley secured 332 marks. If she secured 83 % makes, find the maximum marks.
Solution:
Let the maximum marks be m.
Ashley’s marks = 83% of m
Ashley secured 332 marks
Therefore, 83% of m = 332
⇒ 83/100 × m = 332
⇒ m = (332 × 100)/83
⇒ m =33200/83
⇒ m = 400
Therefore, Ashley got 332 marks out of 400 marks.
2. An alloy contains 26 %
of copper. What quantity of alloy is required to get 260 g of copper?
Solution:
Let the quantity
of alloy required = m g
Then 26 % of m =260
g
⇒ 26/100 × m = 260 g
⇒ m = (260 × 100)/26 g
⇒ m = 26000/26 g
⇒ m = 1000 g
3. There are 50 students in a class. If 14% are absent on a particular
day, find the number of students present in the class.
Solution:
Number of students absent on a particular
day = 14 % of 50
i.e., 14/100 × 50 = 7
Therefore, the number of students present =
50 – 7 = 43 students.
4. In a basket of apples, 12% of them are rotten and 66 are in good
condition. Find the total number of apples in the basket.
Solution:
Let the total number of apples in the
basket be m
12 % of the apples are rotten, and apples
in good condition are 66
Therefore, according to the question,
88% of m = 66
⟹ 88/100 × m = 66
⟹ m = (66 × 100)/88
⟹ m = 3 × 25
⟹ m = 75
Therefore, total number of apples in the
basket is 75.
5. In an examination, 300 students appeared. Out of these students; 28
% got first division, 54 % got second division and the remaining just passed.
Assuming that no student failed; find the number of students who just passed.
Solution:
The number of students with first division
= 28 % of 300
= 28/100 × 300
= 8400/100
= 84
And, the number of students with second
division = 54 % of 300
= 54/100 × 300
=16200/100
= 162
Therefore, the number of students who just
passed = 300 – (84 + 162)
= 54
Real Life Application of Percentage:
Application of the percent is very common in our day-to-day life. Let us consider some examples.
6. In a school of 970 students, 60% are boys. Find the number of girls in the school.
Solution:
Total students = 970
Number of boys = 60% of 970
= \(\frac{60}{100}\) × 970
= \(\frac{3}{5}\) × 970
= 582
Number of girls = 970 – 582 = 388
6. George earns $ 4252 per month. He spends 25% of his income on education of his son. What amount does he spend on education of his son per month?
Solution:
Total income per month = $ 4252
Money spent per month on education = 30% of $ 4252
= $ \(\frac{25}{100}\) × 4252
= $ 1063
Therefore, George spends $ 1063 per month on education of his son.
Worksheet on Word Problems on Percentage
Questions and Answers on Word Problems on Percentage:
1. In a class 60% of the students are girls. If the total number of students is 30, what is the number of boys?
Answer: 12
2. Emma scores 72 marks out of 80 in her English exam. Convert her marks into percent.
Answer: 90%
3. Mason was able to sell 35% of his vegetables before noon. If Mason had 200 kg of vegetables in the morning, how many grams of vegetables was he able to see by noon?
Answer: 70 kg
4. Alexander was able to cover 25% of 150 km journey in the morning. What percent of journey is still left to be covered?
Answer: 112.5 km
5. A cow gives 24 l milk each day. If the milkman sells 75% of the milk, how many liters of milk is left with him?
Answer: 6 l
6. While shopping Grace spent 90% of the money she had. If she had $ 4500 on shopping, what was the amount of money she spent?
Answer: $ 4050
Percentage of the given Quantity
How much Percentage One Quantity is of Another?
Real Life Problems on Percentage
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